뚱2's Story

링크 : http://blog.naver.com/thx4alice?Redirect=Log&logNo=110023260951 

링크 : http://www.dotnetcurry.com/ShowArticle.aspx?ID=564 

링크 : http://tech.pro/tutorial/798/csharp-tutorial-xml-serialization 

링크 : http://msdn.microsoft.com/ko-kr/library/58a18dwa.aspx

A long while ago we posted a tutorial on how to serialize objects to a binary file. While this is very useful, unfortunately the resulting file is not very human readable. In this tutorial, I'm going to demonstrate how to serialize your own objects to and from an XML file.

Since .NET can use reflection to get property names, basic serialization is unbelievably simple. It only gets slightly difficult when you want to name your XML tags differently than your property names (but still not very hard). If you've ever used an XML serialization package in C++ like boost, tinyXML, or libXML2, you'll see how comparatively easy C# is to use.

Let's start with a basic example. Below is an object that stores some information about a movie.

public class Movie
{
  public string Title
  { get; set; }

  public int Rating
  { get; set; }

  public DateTime ReleaseDate
  { get; set; }
}

All right, now that we have an object, let's write a function that will save it to XML.

static public void SerializeToXML(Movie movie)
{
  XmlSerializer serializer = new XmlSerializer(typeof(Movie));
  TextWriter textWriter = new StreamWriter(@"C:\movie.xml");
  serializer.Serialize(textWriter, movie);
  textWriter.Close();
}

The first thing I do is create an XMLSerializer (located in the System.Xml.Serialization namespace) that will serialize objects of type Movie. The XMLSerializer will serialize objects to a stream, so we'll have to create one of those next. In this case, I want to serialize it to a file, so I create a TextWriter. I then simply call Serialize on the XMLSerializer passing in the stream (textWriter) and the object (movie). Lastly I close the TextWriter because you should always close opened files. That's it! Let's create a movie object and see how this is used.

static void Main(string[] args)
{
  Movie movie = new Movie();
  movie.Title = "Starship Troopers";
  movie.ReleaseDate = DateTime.Parse("11/7/1997");
  movie.Rating = 6.9f;

  SerializeToXML(movie);
}

static public void SerializeToXML(Movie movie)
{
  XmlSerializer serializer = new XmlSerializer(typeof(Movie));
  TextWriter textWriter = new StreamWriter(@"C:\movie.xml");
  serializer.Serialize(textWriter, movie);
  textWriter.Close();
}

After this code executes, we'll have an XML file with the contents of our movie object.

<?xml version="1.0" encoding="utf-8"?>
<Movie xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <Title>Starship Troopers</Title>
  <Rating>6.9</Rating>
  <ReleaseDate>1997-11-07T00:00:00</ReleaseDate>
</Movie>

If you noticed, all of the XML tag names are the same as the property names. If we want to change those, we can simply add an attribute above each property that sets the tag name.

public class Movie
{
  [XmlElement("MovieName")]
  public string Title
  { get; set; }

  [XmlElement("MovieRating")]
  public float Rating
  { get; set; }

  [XmlElement("MovieReleaseDate")]
  public DateTime ReleaseDate
  { get; set; }
}

Now when the same code is executed again, we get our custom tag names.

<?xml version="1.0" encoding="utf-8"?>
<Movie xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <MovieName>Starship Troopers</MovieName>
  <MovieRating>6.9</MovieRating>
  <MovieReleaseDate>1997-11-07T00:00:00</MovieReleaseDate>
</Movie>

Sometimes, in XML, you want information stored as an attribute of another tag instead of a tag by itself. This can be easily accomplished with another property attribute.

public class Movie
{
  [XmlAttribute("MovieName")]
  public string Title
  { get; set; }

  [XmlElement("MovieRating")]
  public float Rating
  { get; set; }

  [XmlElement("MovieReleaseDate")]
  public DateTime ReleaseDate
  { get; set; }
}

With this code, MovieName will now be an attribute on the Movie tag.

<?xml version="1.0" encoding="utf-8"?>
<Movie xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:xsd="http://www.w3.org/2001/XMLSchema" 
    MovieName="Starship Troopers">
  <MovieRating>6.9</MovieRating>
  <MovieReleaseDate>1997-11-07T00:00:00</MovieReleaseDate>
</Movie>

Let's move on to something a little more interesting. Let's create another movie and serialize a List of them to our XML file. Here's the modified code to do just that:

static void Main(string[] args)
{
  Movie movie = new Movie();
  movie.Title = "Starship Troopers";
  movie.ReleaseDate = DateTime.Parse("11/7/1997");
  movie.Rating = 6.9f;

  Movie movie2 = new Movie();
  movie2.Title = "Ace Ventura: When Nature Calls";
  movie2.ReleaseDate = DateTime.Parse("11/10/1995");
  movie2.Rating = 5.4f;

  List<Movie> movies = new List<Movie>() { movie, movie2 };

  SerializeToXML(movies);
}

static public void SerializeToXML(List<Movie> movies)
{
  XmlSerializer serializer = new XmlSerializer(typeof(List<Movie>));
  TextWriter textWriter = new StreamWriter(@"C:\movie.xml");
  serializer.Serialize(textWriter, movies);
  textWriter.Close();
}

Now we have XML that looks like this:

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfMovie xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <Movie MovieName="Starship Troopers">
    <MovieRating>6.9</MovieRating>
    <MovieReleaseDate>1997-11-07T00:00:00</MovieReleaseDate>
  </Movie>
  <Movie MovieName="Ace Ventura: When Nature Calls">
    <MovieRating>5.4</MovieRating>
    <MovieReleaseDate>1995-11-10T00:00:00</MovieReleaseDate>
  </Movie>
</ArrayOfMovie>

Ok, so you can see how easy it is to get your objects into an XML document. Let's now look at how to read an XML document back into our objects - deserialization. The process of deserializing is very similar to what we did for serialization.

static List<Movie> DeserializeFromXML()
{
   XmlSerializer deserializer = new XmlSerializer(typeof(List<Movie>));
   TextReader textReader = new StreamReader(@"C:\movie.xml");
   List<Movie> movies; 
   movies = (List<Movie>)deserializer.Deserialize(textReader);
   textReader.Close();

   return movies;
}

Just like before, we first create an XmlSerializer that can deserialize objects of type List\. The XmlSerializer also deserializes from a stream, so we create a file stream from our XML file. We then simply call Deserialize on the stream and cast the output to our desired type. Now the movies List is populated with objects that we previously serialized to the XML file.

The deserializer is very good at handling missing pieces of information in your XML file. Let's say the second movie didn't have the MovieName attribute on the Movie tag. When the XML file is deserialized, it simply populates that field with null. If MovieRating wasn't there, you'd receive 0. Since a DateTime object can't be null, if MovieReleaseDate was missing, you'd receive DateTime.MinValue (1/1/0001 12:00:00AM).

If the XML document contains invalid syntax, like say the first opening Movie tag was missing, the Deserialize call will fail with an InvalidOperationException. It will also be kind enough to specify the location in the file where it encountered the error (line number, column number).

One thing to remember is that the basic XML serialization won't maintain references. Let's say I populated my movies list with the same movie reference multiple times:

Movie movie = new Movie();
movie.Title = "Starship Troopers";
movie.ReleaseDate = DateTime.Parse("11/7/1997");
movie.Rating = 6.9f;

List<Movie> movies = new List<Movie>() { movie, movie };

Now I have a list containing two of the exact same movie reference. When I serialize and deserialize this list, it will be converted to two separate instances of the movie object - they would just have the same information. Along this same line, the XMLSerializer also doesn't support circular references. If you need this kind of flexibility, you should consider binary serialization.

There's still a lot to cover when it comes to XML serialization, but I think this tutorial covers enough of the basics to get things rolling.

링크 : http://www.cyworld.com/programer1234/9368817 

출력창에 위와같이 출력이 된다.

해당 라인을 더블클릭 하면은

실제 소스페이지의 라인으로 이동한다.

using System;

namespace KIS.Util
{
    /// <summary>
    /// 디버깅을 도와주는 유틸 클래스
    /// </summary>
    public static class MyDebug
    {
        /// <summary>
        /// 현재까지 스택트레이스를 출력한다.
        /// </summary>
        public static void GetStackTrace()
        {
            System.Diagnostics.Debug.Write(Environment.StackTrace);
        }

        /// <summary>
        /// 콘솔에 스트릴을 출력한다.
        /// </summary>
        /// <param name="format"></param>
        /// <param name="args"></param>
        public static void PrintConsole(string format, params object[] args)
        {
            string msg = string.Format(format, args);
            System.Console.Write(msg);
        }

        /// <summary>
        /// 현재 파일 이름
        /// </summary>
        public static string CurrentFile
        {
            get
            {
                return new System.Diagnostics.StackTrace(true).GetFrame(1).GetFileName();           
            }
        }

        /// <summary>
        /// 현재 파일의 라인번호
        /// </summary>
        public static int CurrentLine
        {
            get
            {
                return new System.Diagnostics.StackTrace(true).GetFrame(1).GetFileLineNumber();
            }
        }

        public static void TODO(string format, params object[] args)
        {
            string file_name    = new System.Diagnostics.StackTrace(true).GetFrame(1).GetFileName();
            int    file_number  = new System.Diagnostics.StackTrace(true).GetFrame(1).GetFileLineNumber();
            string msg  = string.Format(format, args);
            string todo = string.Format("{0}({1}) : {2}", file_name, file_number, msg);
            System.Console.WriteLine(todo);
        }
    }
}

링크 (Form.Dispose) : http://msdn.microsoft.com/ko-kr/library/aw58wzka(v=vs.90).aspx

링크 (Form.Close) : http://msdn.microsoft.com/ko-kr/library/system.windows.forms.form.close(v=vs.90).aspx 

모달리스로 닫을시에는 Form.Close()를 호출

모달로 닫을시에는 Form.DialogResult 프로퍼티에 값을 대입

링크 : http://msdn.microsoft.com/ko-kr/library/k9x6w0hc(v=vs.80).aspx 

public class Bus
{
    // Static constructor:
    static Bus()
    {
        System.Console.WriteLine("The static constructor invoked.");
    }

    public static void Drive()
    {
        System.Console.WriteLine("The Drive method invoked.");
    }
}

class TestBus
{
    static void Main()
    {
        Bus.Drive();
    }
}

링크 : http://msdn.microsoft.com/ko-kr/library/system.reflection.assembly.load.aspx

어셈블리를 로드합니다.

이 멤버는 오버로드됩니다. 구문, 사용법 및 예제를 비롯하여 이 멤버에 대한 자세한 내용을 보려면 오버로드 목록에서 이름을 클릭합니다.

오버로드 목록

---

	이름	설명
	Load(AssemblyName)	해당 AssemblyName이 지정된 어셈블리를 로드합니다.
	Load(Byte[])	내보낸 어셈블리가 포함된 COFF(Common Object File Format) 기반 이미지를 사용하여 어셈블리를 로드합니다.이 어셈블리는 호출자의 응용 프로그램 도메인에 로드됩니다.
	Load(String)	긴 형식의 이름으로 지정된 어셈블리를 로드합니다.
	Load(AssemblyName, Evidence)	사용되지 않습니다. 해당 AssemblyName이 지정된 어셈블리를 로드합니다.어셈블리는 제공된 증명을 사용하여 호출자의 도메인에 로드됩니다.
	Load(Byte[], Byte[])	생성된 어셈블리가 들어 있고 경우에 따라 어셈블리에 대한 기호도 포함하는 COFF(공용 개체 파일 형식) 기반 이미지를 사용하여 어셈블리를 로드합니다.이 어셈블리는 호출자의 응용 프로그램 도메인에 로드됩니다.
	Load(String, Evidence)	사용되지 않습니다. 해당 표시 이름이 지정된 어셈블리를 로드한 다음 제공된 증명을 사용하여 이 어셈블리를 호출자의 도메인에 로드합니다.
	Load(Byte[], Byte[], Evidence)	사용되지 않습니다. 생성된 어셈블리가 들어 있고 경우에 따라 어셈블리에 대한 기호 및 증명 정보도 포함하는 COFF(공용 개체 파일 형식) 기반 이미지를 사용하여 어셈블리를 로드합니다.이 어셈블리는 호출자의 응용 프로그램 도메인에 로드됩니다.
	Load(Byte[], Byte[], SecurityContextSource)	생성된 어셈블리가 들어 있고 경우에 따라 기호도 포함하고 보안 컨텍스트의 소스도 지정하는 COFF(공용 개체 파일 형식) 기반 이미지를 사용하여 어셈블리를 로드합니다.이 어셈블리는 호출자의 응용 프로그램 도메인에 로드됩니다.

위쪽

선언할때 줄 잘 맞춰서 코딩해 놨는데 공백이 사라지는 억울함이....

도구 -> 옵션 -> 텍스트 편집기 -> C# -> 서식 -> 간격 -> 기타 간격 옵션을 설정합니다. -> 선언문의 공백을 무시합니다.

' 체크 '

링크 : http://msdn.microsoft.com/ko-kr/library/cscsdfbt(VS.80).aspx 

호환되는 참조 형식 간에 변환을 수행하는 데 사용됩니다. 예를 들면 다음과 같습니다.

string s = someObject as string;
if (s != null)
{
    // someObject is a string.
}

expression as type

expression is type ? (type)expression : (type)null

// cs_keyword_as.cs
// The as operator.
using System;
class Class1
{
}

class Class2
{
}

class MainClass
{
    static void Main()
    {
        object[] objArray = new object[6];
        objArray[0] = new Class1();
        objArray[1] = new Class2();
        objArray[2] = "hello";
        objArray[3] = 123;
        objArray[4] = 123.4;
        objArray[5] = null;

        for (int i = 0; i < objArray.Length; ++i)
        {
            string s = objArray[i] as string;
            Console.Write("{0}:", i);
            if (s != null)
            {
                Console.WriteLine("'" + s + "'");
            }
            else
            {
                Console.WriteLine("not a string");
            }
        }
    }
}

0:not a string
1:not a string
2:'hello'
3:not a string
4:not a string
5:not a string

아는 동생이 알려주길래 얼른 사용해봄 나중을 위해서 기록...

private void GetDebugInfo()
{
    string szDebugInfo = string.Empty;

    System.Diagnostics.StackTrace trace = new System.Diagnostics.StackTrace(true);

    System.Diagnostics.Debug.Write("*******************************");
    for(int i=1; i<trace.FrameCount; i++)
    {
        if(trace.GetFrame(i).GetFileName() != null)
        {
            if(trace.GetFrame(i).GetFileName() != String.Empty)
                 System.Diagnostics.Debug.Write(trace.GetFrame(i).ToString());
        }
    }
    System.Diagnostics.Debug.Write("*******************************");
}

링크 : http://msdn.microsoft.com/ko-kr/library/system.runtime.interopservices.dllimportattribute_members(v=vs.90).aspx 

참조 : http://blog.naver.com/luvinuns?Redirect=Log&logNo=90051065276

링크 : http://support.microsoft.com/kb/315582 

비동기로 UI 호출 하기 : http://jongkok4.net/entry/%C6%DFc-UI-%BE%B2%B7%B9%B5%E5-%B8%B6%BC%A3%B8%B5-Invoke-BeginInvoke?TSSESSIONjongkok4net=6e5ec00b34c31e0126e9a64412f7a627